WebAn AP consists of 50 terms of which 3 rd term is 12 and the last term is 106. Find the 29 th term. Medium View solution > View more More From Chapter Arithmetic Progressions … Web5 jan. 2024 · How many terms of the AP : -15,-13,-11..... Are needed to make the sum -55? Explain the reason for the double… Get the answers you need, now! p7aayz5pagupta p7aayz5pagupta 06.01.2024 ... 2 x 4 has at least one real root e) none? Previous Next Advertisement We're in the know
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Web18 aug. 2024 · The AP: -6, -11/2, -5, -9/2,…… To find We need to find how many terms of a series are zero. Solution The common difference between terms d is -11/2- (-6) =1/2. … WebThe AP is -6, -11/2, -5, … It is an AP with the first term as -6 and the common ratio is 1/2. Sn = -25 = (n/2) [2a + (n-1)d] = (n/2) [-12 + (n-1)* (1/2)] = (n/2) [-12–1/2 + (n/2)] = (n/2) [-25/2 + (n/2)] -25*4 = n [-25+n] n^2–25n+100 = 0 (n-20) (n-5) = 0 n = 20 or 5. So either 5 terms or 20 terms of the AP will add up to -25. Answer. 2.1K views
Webwe need to find the sum of how many terms of the AP is 250 Consider the given information AP = 7 , 11 , 15 . . . . . First term ( a ) = 7 Common difference = ( 2nd term - 1st term ) = ( 3rd term - 2nd term ) => ( 7 - 11 ) = ( 15 - 11 ) => ( 4 ) = ( 4 ) Common difference ( d ) = 4 Using the formula ; Here, a = first term d = common difference WebHow many terms of the A.P. −6,− 211,−5... are needed to get the sum −25? Medium Solution Verified by Toppr A.P =−6,− 211,−5... Here,a=−6, d=− 211−−(6)= 2−11+12= 21 …
WebGiven,a=−6d=− 211−(−6)= 21Formula,S n= 2n[2a+(n−1)d]−25= 2n[2(−6)+(n−1) 21]−50=n[ 2−24+n−1]n 2−25n+100=0(n−20)(n−5)=0∴n=5,20Therefore the number of terms … Web30 mrt. 2024 · AP is of the form 6, 11/2, 5 . Here First term = a = 6 Common difference = d = 11/2 ( 6) = 11/2 + 6 = ( 11 + 12 )/2 = 1/2 & Sum of n terms = Sn = 25 We need to find n We know that Sn = n/2 [2a + (n 1)d] Here, Sn = 25 , a = 6 , d =1/2 Putting values 25 = …
WebTherefore, the sum of the first 5 terms or the sum of the first 11 terms of an AP is equal to -55. The 11 terms of the series are -15, -13, -11, -9, -7, -5, -3, -1, 1, 3, 5. The reason for …
WebHow many terms of the A.P -6, -11/2, -5, -9/2........are needed to give their sum zero. arithmetic progression cbse class-10 1 Answer +2 votes answered Sep 29, 2024 by … how to start mate desktop from terminalWebWhere a is first term of AP and d is difference between two consecutive terms of AP. Calculation: Given series is 2, 4, 6, 8, 10,..... a = 2 and d = 2. Let sum of n terms of AP is … react images upload npmWeb9 dec. 2024 · Answer: No of terms = 5 ,20 Step-by-step explanation: Given : AP : -6, -11/2 , -5 To find: No of terms to give sum = -25 Steps: Firstly e calculate the common … how to start making youtube gaming videosWebGiven AP is : 1, 6, 11, 16…… First term, a = 1 ; Common difference = 5. Sum of n terms of AP, Sn = (n/2)[2a+(n-1)d] Let there be n terms in the AP such that Sn= 148. 148= … how to start marigolds from seed indoorsWeb29 mrt. 2024 · Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo. react images uploadWebFirst term of the AP = 65 Common difference = 60 − 65 = −5 Let the sum of the first x terms of the AP be 0. Sum of first x terms = x 2 [2×65+(x−1)(−5)]=0 ⇒ x 2 [130+(−5x+5)]=0 ⇒x(130−5x+5)=0 ⇒x(135−5x)=0 Now, either x = 0 or 135 − 5x = 0. Since the number of terms cannot be 0, x≠0. ∴ 135 − 5 x = 0 ⇒ 135 = 5 x ⇒ x = 27 react images showsWebAP = 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15 Given, a = 1, d = 2-1 = 1 and a n = 15 Now, by the formula we know; S n = n/2 [2a + (n − 1) × d] S 15 = 15/2 [2.1+ (15-1).1] = 15/2 [2+14] = 15/2 [16] = 15 x 8 = 120 Hence, … react img max width